Referring back to the scenario in the previous few questions, suppose the app company wanted to...

Referring back to the scenario in the previous few questions, suppose the app company wanted to make a 99% confidence interval for the true satisfaction rate with a margin of error of 2%.

How big a sample would they need to take?

4147.36

3382

3381.42

4148

Solutions

Expert Solution

Solution :

Given that,

= 0.5

1 - = 1 - 0.5 = 0.5

margin of error = E = 2% = 0.02

At 99% confidence level the z is,

= 1 - 99%

= 1 - 0.99 = 0.01

/2 = 0.005

Z/2 = 2.576 ( Using z table )

Sample size = n = (Z/2 / E)2 * * (1 - )

= (2.576 / 0.02)2 * 0.5 * 0.5

=4147.36

Sample size = 4148 rounded

orchestra answered 1 year ago

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