In: Statistics and Probability
Confidence Levels: Given specific sample data (for example poll results from 1000 people of whom 14% indicated their favorite pie was chocolate) which confidence interval is wider: the 95% confidence interval or the 80% confidence interval? Why is it wider?
Where can I find the correct formula to answer this question?
Solution :
Given that,
n = 1000
Point estimate = sample proportion = = 014
1 - = 1 - 0.14 = 0.86
a) At 95% confidence level
= 1 - 95%
=1 - 0.95 =0.05
/2
= 0.025
Z/2
= Z0.025 = 1.960
Margin of error = E = Z / 2 * (( * (1 - )) / n)
= 1.96 (((0.14 * 0.86) / 1000)
= 0.022
A 95% confidence interval for population proportion is ,
- E < < + E
0.14 - 0.022 < < 0.14 + 0.022
( 0.118 < < 0.162 )
b) At 80% confidence level
= 1 - 80%
=1 - 0.80 =0.20
/2
= 0.10
Z/2
= Z0.10 = 1.282
Margin of error = E = Z / 2 * (( * (1 - )) / n)
= 1.282 (((0.14 * 0.86) / 1000)
= 0.014
A 80% confidence interval for population proportion is ,
- E < < + E
0.14 - 0.014 < < 0.14 + 0.014
( 0.126 < < 0.154 )
The 95% confidence interval is wider