In: Statistics and Probability
Use the given degree of confidence and sample data to construct a confidence interval for the population mean μ. Assume that the population has a normal distribution. A laboratory tested twelve chicken eggs and found that the mean amount of cholesterol was 185 milligrams with s = 17.6 milligrams. Construct a 95% confidence interval for the true mean cholesterol content of all such eggs.
Solution :
Given that,
Point estimate = sample mean =
= 185
sample standard deviation = s = 17.6
sample size = n = 12
Degrees of freedom = df = n - 1 = 12 - 1 = 11
At 95% confidence level the t is ,
= 1 - 95% = 1 - 0.95 = 0.05
/ 2 = 0.05 / 2 = 0.025
t
/2,df = t0.025,11 = 2.201
Margin of error = E = t/2,df
* (s /
n)
= 2.201 * (17.6 /
12)
= 11.2
The 95% confidence interval estimate of the population mean is,
- E <
<
+ E
185 - 11.2 <
< 185 + 11.2
173.8 <
< 196.2
(173.8 , 196.2)