Question

In: Chemistry

How much CO2 ir released (in pounds) per year of your normal driving? comment on the...

How much CO2 ir released (in pounds) per year of your normal driving? comment on the size of your answer. CO2 is a greenhouse gas) how cound you reduce "carbon footprint'.

- Assume gasoline is mostly octane

- how many miles do you drive per week or per month

- how many miles per year?

- Gas mileage of your car> (# miles per gallon of gas)

- stoichiometry of the reaction

Solutions

Expert Solution

Ans. a. Average driving per month = 60 miles

b. Average driving per year = 12 months x 60 miles                     [1 year = 12 months]

                                    = 720 miles

c. Gas mileage of my car = 28.30 miles per gallon

            Total gasoline used in 1 year = total driving in 1 year / Average mileage of car

                                                = 720 miles/ (28.30 miles / gallon) = 25.44 gallon

d. Stoichiometry of reaction:       C8H18 + (25/2) O2 -----------> 8CO2 + 9 H2O

molecular mass of gasoline (C8H18) = 114.23 gram/ mol

molecular mass of CO2 = 44.00 g /mol

Total mass of CO2 produced from 1 mol octane = 8 moles CO2 x molar mass of 1 CO2

                                                = 8 mol x 44.00 g /mol = 352 gram

From the stoichiometry of reaction, 114.28 g (= 1 mol octane) produces 352.0 g CO2.

Or, 114.28 kg octane produces 352.0 kg CO2 (mass converted to kg).

Density of gasoline = 0.702 kg/ L                                           [1 L = 0.264172 gallon]

                                    = 0.702 kg/ (0.264172 gallon) = 2.66 kg/ gallon

Total mass of gasoline required in 1 year

= volume of gasoline required in 1 year x density of gasoline

                                    = 25.44 gallon x (2.66 kg/ gallon) = 67.67 kg

Now, we have 114.28 kg octane produces 352.0 kg CO2- stoichiometry of reaction.

So, mass of CO2 produced from 67.67 kg gasoline (CO2 produced per year)

                                                = (352.0 kg CO2 / 114.28 kg octane) x 67.67 kg octane

                                                = 208.43 kg CO2

                                                = 459.52 lb CO2                     [1 kg = 2.20462 lb]


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