In: Chemistry
How much CO2 ir released (in pounds) per year of your normal driving? comment on the size of your answer. CO2 is a greenhouse gas) how cound you reduce "carbon footprint'.
- Assume gasoline is mostly octane
- how many miles do you drive per week or per month
- how many miles per year?
- Gas mileage of your car> (# miles per gallon of gas)
- stoichiometry of the reaction
Ans. a. Average driving per month = 60 miles
b. Average driving per year = 12 months x 60 miles [1 year = 12 months]
= 720 miles
c. Gas mileage of my car = 28.30 miles per gallon
Total gasoline used in 1 year = total driving in 1 year / Average mileage of car
= 720 miles/ (28.30 miles / gallon) = 25.44 gallon
d. Stoichiometry of reaction: C8H18 + (25/2) O2 -----------> 8CO2 + 9 H2O
molecular mass of gasoline (C8H18) = 114.23 gram/ mol
molecular mass of CO2 = 44.00 g /mol
Total mass of CO2 produced from 1 mol octane = 8 moles CO2 x molar mass of 1 CO2
= 8 mol x 44.00 g /mol = 352 gram
From the stoichiometry of reaction, 114.28 g (= 1 mol octane) produces 352.0 g CO2.
Or, 114.28 kg octane produces 352.0 kg CO2 (mass converted to kg).
Density of gasoline = 0.702 kg/ L [1 L = 0.264172 gallon]
= 0.702 kg/ (0.264172 gallon) = 2.66 kg/ gallon
Total mass of gasoline required in 1 year
= volume of gasoline required in 1 year x density of gasoline
= 25.44 gallon x (2.66 kg/ gallon) = 67.67 kg
Now, we have 114.28 kg octane produces 352.0 kg CO2- stoichiometry of reaction.
So, mass of CO2 produced from 67.67 kg gasoline (CO2 produced per year)
= (352.0 kg CO2 / 114.28 kg octane) x 67.67 kg octane
= 208.43 kg CO2
= 459.52 lb CO2 [1 kg = 2.20462 lb]