In: Chemistry
Acetylene (C2H2) undergoes combustion in excess oxygen to generate gaseous carbon dioxide and water. Given (delta)H degrees F[CO2(g)] = -393.5 kJ/mol, (delta)H degrees F[H2O(g)] = -241.8 kJ/mol, and (delta)H degrees F [C2H2(g)] = 226.6 kJ/mol, how much energy is released (kJ) when 10.5 moles of acetylene is burned?
2.5108 MJ |
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26.4 MJ |
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13.2 MJ |
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52.7 MJ |
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9.05 MJ options listed above |
2C2H2 (g)+ 3O2(g) -----------> 4Co2(g) +2H2O(g)
H rxn = Hf products - Hf reactants
= 4*-393.5+2*-241.8- (2*226.6+0)
= -2510.8Kj
2C2H2 (g)+ 3O2(g) -----------> 4Co2(g) +2H2O(g) H rxn = -2510.8KJ
2 moles of C2H2 released energy is -2510.8KJ
10.5 moles of C2H2 released energy is = -2510.8*10.5/2 = -13181.7KJ = 13.2*10^6J = 13.2MJ >>>>>answer