Question

In: Chemistry

Acetylene (C2H2) undergoes combustion in excess oxygen to generate gaseous carbon dioxide and water. Given (delta)H...

Acetylene (C2H2) undergoes combustion in excess oxygen to generate gaseous carbon dioxide and water. Given (delta)H degrees F[CO2(g)] = -393.5 kJ/mol, (delta)H degrees F[H2O(g)] = -241.8 kJ/mol, and (delta)H degrees F [C2H2(g)] = 226.6 kJ/mol, how much energy is released (kJ) when 10.5 moles of acetylene is burned?

2.5108 MJ

26.4 MJ

13.2 MJ

52.7 MJ

9.05 MJ

options listed above

Solutions

Expert Solution

2C2H2 (g)+ 3O2(g) -----------> 4Co2(g) +2H2O(g)

H rxn   = Hf products - Hf reactants

               = 4*-393.5+2*-241.8- (2*226.6+0)

               = -2510.8Kj

2C2H2 (g)+ 3O2(g) -----------> 4Co2(g) +2H2O(g)    H rxn   = -2510.8KJ

2 moles of C2H2 released energy is -2510.8KJ

10.5 moles of C2H2 released energy is = -2510.8*10.5/2   = -13181.7KJ   = 13.2*10^6J   = 13.2MJ >>>>>answer


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