Question

In: Chemistry

Gaseous butane CH3CH22CH3 will react with gaseous oxygen O2 to produce gaseous carbon dioxide CO2 and...

Gaseous butane

CH3CH22CH3

will react with gaseous oxygen

O2

to produce gaseous carbon dioxide

CO2

and gaseous water

H2O

. Suppose 1.74 g of butane is mixed with 12. g of oxygen. Calculate the minimum mass of butane that could be left over by the chemical reaction. Be sure your answer has the correct number of significant digits.

Solutions

Expert Solution

2CH3-CH2-CH2-CH3 + 9O2 -------------> 8CO2 + 10H2O

no of moles of Butane   = W/G.M.Wt

                                     = 1.74/58   = 0.03 moles

no of moles of O2   = W/G.M.Wt

                               = 12/32   = 0.375 moles

from balanced equation

2 moles of butane react with 9 moles of O2

0.03 moles of butane react with = 9*0.03/2   = 0.135 moles O2 is required.

O2 is excess reagent.

zero amount of butane is left.


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