Question

In: Statistics and Probability

Suppose the mean Verbal SAT score for the population of first graders in New York City...

Suppose the mean Verbal SAT score for the population of first graders in New York City is 520, with a standard deviation of 95. An investigator believes that the mean Verbal SAT scores of first year Buying and Merchandising majors is significantly different from the mean of the population. The mean of a sample of 36 first year Buying and Merchandising majors is 548.Use the six-step approach to test the investigator’s prediction at the .05 level of significance.

NOTE: The steps must be clearly and neatly indicated. (2, 5, 3, 8, 3, 4 = 25 points)

Solutions

Expert Solution

Solution:

Step 1:

The null and alternative hypotheses are as follows:

H​​​​​​0 : μ = 520 i.e. The population mean of the Verbal SAT scores of first year Buying and Merchandising majors is 520.

H​​​​​1 : μ ≠ 520 i.e. The population mean of the Verbal SAT scores of first year Buying and Merchandising majors is not equal to 520.

Step 2:

To test hypothesis we shall use one sample z-test for mean. The test statistic is given as follows:

Where, x̄ is sample mean, μ is hypothesized value of population mean, σ is population standard deviation and n is sample size.

We have, x̄ = 548, μ = 520, σ = 95 and n = 36

The value of the test statistic is 1.76842.

Step 3:

Since, our test is two-tailed test, therefore we shall obtain two-tailed p-value for the test statistic. The two-tailed p-value is given as follows:

p-value = 2.P(Z > value of the test statistic)

Hence, p-value = 2.P(Z > 1.76842)

p-value = 0.07699

The p-value is 0.07699.

Step 4:

The specified significance level is 0.05

Step 5:

We make decision rule as follows:

If p-value is greater than the significance level, then we fail to reject the null hypothesis (H​​​​​​0) at given significance level.

If p-value is less than the significance level, then we reject the null hypothesis (H​​​​​​0) at given significance level.

We have, p-value = 0.07699 and significance level = 0.05

(0.07699 > 0.05)

Since, p-value is greater than the significance level of 0.05, therefore we shall be fail to reject the null hypothesis (H​​​​​​0) at 0.05 significance level.

Step 6 :

Conclusion : At significance level of 0.05, there is not sufficient evidence to support the investigator claim that the mean Verbal SAT scores of first year Buying and Merchandising majors is significantly different from the mean of the population.

Please rate the answer. Thank you.


Related Solutions

The mean Verbal SAT score for the population of first students at Radford is 520. The...
The mean Verbal SAT score for the population of first students at Radford is 520. The standard deviation of scores in this population is 95. An investigator believes that the mean Verbal SAT of first year psychology majors is significantly different from the mean score of the population. The mean of a sample of 36 first year psychology majors is 548. Please test the investigator's prediction using an alpha level of .05. a. Please state both the null and alternative...
The national average SAT score (for verbal and math) is 1028 . Suppose that nothing is...
The national average SAT score (for verbal and math) is 1028 . Suppose that nothing is known about the shape of the distribution and that the standard deviation is 100 . Round the final answer to at least four decimal places and intermediate z -value calculations to two decimal places. 1.If a random sample of 205 scores was selected, find the probability that the sample mean is greater than 1044 . Assume that the sample is taken from a large...
A hypothesis test was conducted to compare the mean SAT-Verbal score of a sample of 10...
A hypothesis test was conducted to compare the mean SAT-Verbal score of a sample of 10 students from one school to the known national norms. In the sample of 10 students, the mean was 555. In the population, SAT-Verbal scores are normed to have a mean of 500 and standard deviation of 100. The two-tailed single sample mean z test resulted in a test statistic of 1.739 and p value of 0.082. At the 0.05 alpha level, the results were...
The national average SAT score (for verbal & math) is 1028. Suppose nothing is known about...
The national average SAT score (for verbal & math) is 1028. Suppose nothing is known about the distribution of individual SAT scores, but it is known that the standard deviation of these scores is 100. If a random sample of 200 scores were selected and the sample mean was calculated to be 1050, would this be surprising? If so, why? If not, why not?
Math SAT Scores (Raw Data, Software Required): Suppose the national mean SAT score in mathematics is...
Math SAT Scores (Raw Data, Software Required): Suppose the national mean SAT score in mathematics is 520. The scores from a random sample of 40 graduates from Stevens High are given in the table below. Use this data to test the claim that the mean SAT score for all Stevens High graduates is the same as the national average. Test this claim at the 0.10 significance level (a) What type of test is this? This is a left-tailed test.This is...
Math SAT Scores (Raw Data, Software Required): Suppose the national mean SAT score in mathematics is...
Math SAT Scores (Raw Data, Software Required): Suppose the national mean SAT score in mathematics is 520. The scores from a random sample of 40 graduates from Stevens High are given in the table below. Use this data to test the claim that the mean SAT score for all Stevens High graduates is the same as the national average. Test this claim at the 0.10 significance level. (a) What type of test is this? This is a left-tailed test. This...
New York City is the most expensive city in the United States for lodging. The mean...
New York City is the most expensive city in the United States for lodging. The mean hotel room rate is $204 per night (USA Today, April 30, 2012). Assume that room rates are normally distributed with a standard deviation of $55. a. What is the probability that a hotel room costs $225 or more per night (to 4 decimals)? b. What is the probability that a hotel room costs less than $140 per night (to 4 decimals)? c. What is...
New York City is the most expensive city in the United States for lodging. The mean...
New York City is the most expensive city in the United States for lodging. The mean hotel room rate is $204 per night. Assume that room rates are normally distributed with a standard deviation of $55. a. What is the probability that a hotel room costs $225 or more per night? b. What is the probability that a hotel room costs less than $140 per night? c. What is the probability that a hotel room costs between $200 and $300...
New York City is the most expensive city in the United States for lodging. The mean...
New York City is the most expensive city in the United States for lodging. The mean hotel room rate is $205 per night (USA Today, April 30, 2012). Assume that room rates are normally distributed with a standard deviation of $55. Use Table 1 in Appendix B. a. What is the probability that a hotel room costs $227 or more per night (to 4 decimals)? b. What is the probability that a hotel room costs less than $143 per night...
New York City is the most expensive city in the United States for lodging. The mean...
New York City is the most expensive city in the United States for lodging. The mean hotel room rate is $205 per night (USA Today, April 30, 2012). Assume that room rates are normally distributed with a standard deviation of $53. Use Table 1 in Appendix B. a. What is the probability that a hotel room costs $224 or more per night (to 4 decimals)? b. What is the probability that a hotel room costs less than $139 per night...
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT