In: Statistics and Probability
Suppose a hospital would like to estimate the proportion of patients who feel that physicians who care for them always communicated effectively when discussing their medical care. A pilot sample of 50 patients found that 36 reported that their physician communicated effectively. Determine the additional number of patients that need to be sampled to construct a 90% confidence interval with a margin of error equal to 8% to estimate this proportion.
The additional number of patients that need to be sampled is _____.
Solution :
Given that,
n = 50
x = 36
Point estimate = sample proportion = = x / n = 36 / 50 = 0.72
1 - = 1 - 0.72 = 0.28
margin of error = E = 0.08
At 90% confidence level
= 1 - 90%
= 1 - 0.90 =0.10
/2
= 0.05
Z/2
= Z0.05 = 1.645
sample size = n = (Z / 2 / E )2 * * (1 - )
= (1.645 / 0.08)2 * 0.72 * 0.28
= 85.23
sample size = n = 86