In: Statistics and Probability
You work for a soft-drink company in the quality control division. You are interested in the standard deviation of one of your production lines as a measure of consistency. The product is intended to have a mean of 12 ounces, and your team would like the standard deviation to be as low as possible. You gather a random sample of 17 containers. Estimate the population standard deviation at a 98% level of confidence.
11.83 | 12.12 | 12.13 | 11.96 | 12.15 | 11.86 |
12.02 | 12.02 | 11.99 | 12.08 | 12 | 11.97 |
11.97 | 11.94 | 11.98 | 12.05 | 11.96 |
(Data checksum: 204.03)
Note: Keep as many decimals as possible while making these calculations. If possible, keep all answers exact by storing answers as variables on your calculator or computer.
a) Find the sample standard deviation:
b) Find the lower and upper χ2 critical values at 98%
confidence:
Lower: Upper:
c) Report your confidence interval for σσ: ( , )
number of observations (n) = 17
a). the necessary calculation table :-
x | |
11.83 | 0.029501 |
12.12 | 0.013981 |
12.13 | 0.016445 |
11.96 | 0.001744 |
12.15 | 0.021975 |
11.86 | 0.020096 |
12.02 | 0.000333 |
12.02 | 0.000333 |
11.99 | 0.000138 |
12.08 | 0.006121 |
12 | 0.000003 |
11.97 | 0.001009 |
11.97 | 0.001009 |
11.94 | 0.003814 |
11.98 | 0.000473 |
12.05 | 0.002327 |
11.96 | 0.001744 |
sum=0.121047 |
sample standard deviation be:-
b). df = (n-1) = (17-1) = 16
chi square critical value for df=16, at 98% confidence (alpha= 0.02) be:-
excel function | critical value | |
=CHISQ.INV.RT(0.99,16) | 5.812212 | |
=CHISQ.INV.RT(0.01,16) | 31.99993 |
c).the 98% confidence interval for the standard deviation be:-
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