In: Statistics and Probability
Here we have to test that
Null hypothesis :
Alternative hypothesis :
where
n = sample size = 43
Sample mean = 33.42
Sample standard deviation = s = 9.98
Here population standard deviation is not known so we use t test.
Test statistic :
t = -1.695 (Round to 3 decimal)
Test statistic = -1.695
Level of significance = = 0.01
Test is left tailed test.
Degrees of freedom = n - 1 = 43 - 1 = 42
t critical value for = 0.01 and df = 42 from excel using function:
=T.INV(0.01,42)
=-2.418
t criticl value = -2.418
Here test statistic > t critical value.
So we fail to reject H0
Conclusion : There is insufficient evidence to show that teenage males consume a mean of less than 36 ounces of soda per day
b)
P value from excel usinf function:
=T.DIST(-1.695, 42, TRUE)
= 0.0487 (Round to 4 decimal
P value = 0.0487
Here p value >
So we fail to reject H0.
Conclusion : There is insufficient evidence to show that teenage males consume a mean of less than 36 ounces of soda per day