Question

In: Statistics and Probability

In a random sample of males, it was found that 23 write with their left hands...

In a random sample of males, it was found that 23 write with their left hands and 217 do not. In a random sample of females, it was found that 65 write with their left hands and 455 do not. We want to use a 0.01 significance level to test the claim that the rate of left-handedness among males is less than that among females. Test the claim using a hypothesis test.

Group of answer choices

A.P value=0.0926; fail to reject H0

B.P value=0.0926; reject H0

C.P value=0.0371; fail to reject H0

D.P value=0.0926; reject H0

Solutions

Expert Solution

x1                =    23 x2                =    65
1=x1/n1 = 0.1060 2=x2/n2 = 0.1429
n1                       = 217 n2                       = 455
estimated prop. diff =p̂1-p̂2    = -0.0369
pooled prop p̂ =(x1+x2)/(n1+n2)= 0.1310
std error Se=√(p̂1*(1-p̂1)*(1/n1+1/n2) = 0.0278
test stat z=(p̂1-p̂2)/Se = -1.325
P value   = 0.0926

since p value >0.01 ; we fail to reject Ho

correct option is A:  .P value=0.0926; fail to reject H0


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