Question

In: Statistics and Probability

Calculate the following probabilities using the standard normal distribution. (Round your answers to four decimal places.)...

Calculate the following probabilities using the standard normal distribution. (Round your answers to four decimal places.) (a) P(0.0 ≤ Z ≤ 1.8) (b) P(−0.1 ≤ Z ≤ 0.0) (c) P(0.0 ≤ Z ≤ 1.46) (d) P(0.3 ≤ Z ≤ 1.58) (e) P(−2.02 ≤ Z ≤ −1.72) (f) P(−0.02 ≤ Z ≤ 3.51) (g) P(Z ≥ 2.10) (h) P(Z ≤ 1.63) (i) P(Z ≥ 6) (j) P(Z ≥ −9)

Solutions

Expert Solution

solution

P(0.0 < Z <1.8 )

= P(Z <1.8 ) - P(Z < 0.0)

Using z table,  

= 0.9641 -0.5

=0.4641

probability=0.4641

(B)P(−0.1 ≤ Z ≤ 0.0)

P(Z <0.0 ) - P(Z < -0.1)

Using z table,  

= 0.5 -0.4602

=0.0398

probability=0.0398

(C)P(0.0 ≤ Z ≤ 1.46)

P(Z <1.46 ) - P(Z < 0.0)

Using z table,  

= 0.9279 -0.5

=0.4279

probability=0.4279

(D)P(0.3 ≤ Z ≤ 1.58)

P(Z <1.58 ) - P(Z < 0.3)

Using z table,  

= 0.9429 -0.6179

=0.3250

probability=0.3250

(E) P(−2.02 ≤ Z ≤ −1.72)

P(Z <-1.72 ) - P(Z < -2.02)

Using z table,  

= 0.0427 - 0.0217

=0.0210

probability=0.0210

(f)P(−0.02 ≤ Z ≤ 3.51)

P(Z <3.51 ) - P(Z < -0.02)

Using z table,  

=0.9998 - 0.4920

=0.5078

probability=0.5078

(g)P(Z ≥ 2.10) =1 - P(Z < 2.10) =1 -0.9821=0.0179

probability=0.0179

(h) P(Z ≤ 1.63) =0.9484

probability=0.9484

(i)P(Z ≥ 6) =1 - P(Z < 6) =1 -1=0

probability=0

(J)P(Z ≥ −9)=1 - P(Z < -9) =1 -0=1

probability=1


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