Question

Calculate the standard error. May normality be assumed? (Round your answers to 4 decimal places.)

	Standard Error	Normality
(a) n = 27, ππ = 0.35		(Click to select)NoYes
(b) n = 48, ππ = 0.53		(Click to select)NoYes
(c) n = 110, ππ = 0.41		(Click to select)YesNo
(d) n = 489, ππ = 0.006		(Click to select)NoYes

Answer 1

Solution:

Given that,

a ) n = 27

= 0.35

1 -   = 1 - 0.35 = 0.65

=   ( 1 - ) / n

=   0.35 * 0.65 / 27

= 0.0918

Standard error = 0.0918

b ) n = 48

   = 0.53

1 -   = 1 - 0.53 = 0.47

=   ( 1 - ) / n

=   0.53 * 0.47 / 48

= 0.0720

Standard error = 0.0720

c ) n = 110

   = 0.41

1 -   = 1 - 0.41 = 0.59

=   ( 1 - ) / n

=   0.41 * 0.59 / 110

= 0.0469

Standard error = 0.0469

d ) n = 489

   = 0.006

1 -   = 1 - 0.006 = 0.994

=   ( 1 - ) / n

=   0.006 * 0.994 / 489

= 0.0035

Standard error = 0.0035