Question

In: Chemistry

What is the expected pH of a 0.250 M solution of oxalic acid with Ka =...

What is the expected pH of a 0.250 M solution of oxalic acid with Ka = 5.37 x 10^-5 ([H+] = 0.002197) and will the pH increase by one unit if the solution is diluted to 0.0250 M?

Expert Solution

[H+] = 0.002197 M

pH = -log [H+] = -log (0.002197)

= 2.66

pH = 2.66

C2H4O2 ---------------> C2H3O2- + H+

0.0250 0 0

0.0250-x x x

Ka = x^2 / 0.0250 - x

5.37 x 10^-5 = x^2 / 0.0250 - x

x = 1.132 x 10^-3

[H+] = 1.132 x 10^-3 M

pH = -log [H+] = -log(1.132 x 10^-3)

= 2.95

pH = 2.95

pH change = 2.95 - 2.66 = 0.29

no , pH will not increase one unit. it only increases 0.29 units

queen_honey_blossom answered 2 years ago

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