Question

In: Statistics and Probability

3) An experiment was performed where HEK 293 cells expressing TLR5 was treated with flagellin and...

3) An experiment was performed where HEK 293 cells expressing TLR5 was treated with flagellin and the following absorbance readings were measured at 655 nm.

No treatment: 0.232, 0.247, 0.239

Flagellin treatment: 0.355, 0.377, 0.350

What is the P-value as calculated by T-test? Assume 2-tails and equal variance among the groups.

Solutions

Expert Solution

Ho :   µ1 - µ2 =   0                  
Ha :   µ1-µ2 ╪   0                  
                          
  
Sample #1   ---->   1                  
mean of sample 1,    x̅1=   0.239                  
standard deviation of sample 1,   s1 =    0.0075                  
size of sample 1,    n1=   3                  
                          
Sample #2   ---->   2                  
mean of sample 2,    x̅2=   0.361                  
standard deviation of sample 2,   s2 =    0.0144                  
size of sample 2,    n2=   3                  
                          
difference in sample means =    x̅1-x̅2 =    0.2393   -   0.4   =   -0.121  
                          
pooled std dev , Sp=   √([(n1 - 1)s1² + (n2 - 1)s2²]/(n1+n2-2)) =    0.0115                  
std error , SE =    Sp*√(1/n1+1/n2) =    0.0094                  
                          
t-statistic = ((x̅1-x̅2)-µd)/SE = (   -0.1213   -   0   ) /    0.01   =   -12.97
                          
Degree of freedom, DF=   n1+n2-2 =    4                  
p-value =        0.0002   (excel function: =T.DIST.2T(t stat,df) )              

orchestra answered 1 year ago
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