Standard reduction potentials are provided for two half reactions that involve the hypothetical metal "M" and...

Standard reduction potentials are provided for two half reactions that involve the hypothetical metal "M" and sulfide ion. Use them to calculate the value of the solubility product constant for the metal sulfide. (Hint: what is the balanced chemical reaction equation for the equilibrium reaction that gives K_sp?)

M²⁺ + 2 e^- ⇌ M(s)	E^o = -0.057 V
MS(s) + 2 e^- ⇌ M(s) + S^2-	E^o = -1.208 V
K_sp of MS(s) =

Expert Solution

Oxidation : M (s) <---------> M2+ + 2e- Eo = -0.057 V

Reduction : MS(s) + 2 e^- <------------> M(s) + S^2- Eo = - 1.208 V

_____________________________________________

Overall : MS(s) <------------> M2+ + S2-

balanced chemical reaction : MS(s) <------------> M2+ + S2-

Eocell = - 1.208 + 0.057

= - 1.151 V

delta Go = - n F Eocell

= - 2 x 96485 x - 1.151

= 222108.5 J

delta Go = - RT ln Ksp

222108.5 = - 8.314 x 298 x ln Ksp

Ksp = 1.17 x 10^-39

Ksp of MS (s) = 1.2 x 10^-39

queen_honey_blossom answered 2 years ago

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