1. Using a table of standard reduction potentials, standard conditions are assumed. (a) Arrange the following...

1. Using a table of standard reduction potentials, standard conditions are assumed.

(a) Arrange the following chemical species: Zn(s), Cl^-(aq), Cu(s), K(s), and H₂(g) in order of their ease of oxidation, from easiest to oxidize to hardest to oxidize.

(b) Arrange the following chemical species: H⁺(aq), I₂(s), Na⁺(aq), Ag⁺(aq), and H₂O(l) in order of their ease of reduction, from easiest to reduce to hardest to reduce.

2. Which of the following reactions is/are product favored?

Zn(s) + I₂(s) ? Zn⁺² (aq) + 2I^-(aq)

2Cl^-(aq) + I₂(s) ? Cl₂(g) + 2I^-(aq)

2Na⁺(aq) + 2Cl^-(aq) ? 2Na(s) + Cl₂(g)

2K(s) + 2H₂O(l) ? 2K⁺(aq) + H₂(g) + 2OH^-(aq)

Solutions

Expert Solution

1 (a). According to their oxidation potential:

Zn(s) Zn²⁺(aq) E⁰ = 0.7618V

2Cl^-(aq) Cl₂(g) E⁰ = -1.36V

Cu(s) Cu²⁺(aq) E⁰ = -0.337V

K(s) K⁺(aq) E⁰ = 2.931V

H₂(g) 2H⁺(aq) E⁰ = 0V

decreasing order of their ease of oxidation is given as:

Cl^-(aq) > Cu(s) > H₂(g) > Zn(s) > K(s)

(b). In the same way the decreasing order of their ease of reduction is given as:

Na⁺(aq) > H₂O(l) > H⁺(aq) > Ag⁺(aq) > I₂(s)

2. The following reactions are favoured -

Zn(s) + I₂(s) Zn⁺² (aq) + 2I^-(aq)

and,

2K(s) + 2H₂O(l) 2K⁺(aq) + H₂(g) + 2OH^-(aq)

queen_honey_blossom answered 1 year ago

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