In: Chemistry
1. Using a table of standard reduction potentials, standard conditions are assumed.
(a) Arrange the following chemical species: Zn(s), Cl-(aq), Cu(s), K(s), and H2(g) in order of their ease of oxidation, from easiest to oxidize to hardest to oxidize.
(b) Arrange the following chemical species: H+(aq), I2(s), Na+(aq), Ag+(aq), and H2O(l) in order of their ease of reduction, from easiest to reduce to hardest to reduce.
2. Which of the following reactions is/are product favored?
Zn(s) + I2(s) ? Zn+2 (aq) + 2I-(aq)
2Cl-(aq) + I2(s) ? Cl2(g) + 2I-(aq)
2Na+(aq) + 2Cl-(aq) ? 2Na(s) + Cl2(g)
2K(s) + 2H2O(l) ? 2K+(aq) + H2(g) + 2OH-(aq)
1 (a). According to their oxidation potential:
Zn(s) Zn2+(aq) E0 = 0.7618V
2Cl-(aq) Cl2(g) E0 = -1.36V
Cu(s) Cu2+(aq) E0 = -0.337V
K(s) K+(aq) E0 = 2.931V
H2(g) 2H+(aq) E0 = 0V
decreasing order of their ease of oxidation is given as:
Cl-(aq) > Cu(s) > H2(g) > Zn(s) > K(s)
(b). In the same way the decreasing order of their ease of reduction is given as:
Na+(aq) > H2O(l) > H+(aq) > Ag+(aq) > I2(s)
2. The following reactions are favoured -
Zn(s) + I2(s) Zn+2 (aq) + 2I-(aq)
and,
2K(s) + 2H2O(l) 2K+(aq) + H2(g) + 2OH-(aq)