Which one of the following salts, when dissolved in water,
produces the solution with the highest...
Which one of the following salts, when dissolved in water,
produces the solution with the highest pH? Which one of the
following salts, when dissolved in water, produces the solution
with the highest pH? CH3NH3I LiClO4 MgO NaHSO 4
determine whether the following salts when dissolved in water
would make the solution acidic, basic or remain neutral. when
making solution acidic or neutral write acid base reaction causing
the soultion to become acidic or basic.
a. KC2H5O2
B. NaNO3
C. NH4NO3
D.NH4F
E.NaHPO4
F. NaCL
G.K2CO3
H.NH4NO3
I. NH4HSO4
Which of the following salts is(are) considered basic when
dissolved in water?
I.NaNO3
II.K3PO4
III.NH4Cl
IV.Na2CO3
a.
I and IV
b.
III and IV
c.
I and II
d.
II and IV
e.
II and III
5. Which of the following when dissolved in water has the
highest concentration of calcium ions?
A. CaCO3;
Ksp
= 8.7 x 10-9
B.
CaF2;
Ksp = 4.0 x 10-11
C. Ca(OH)2
Ksp = 8.0 x 10-6
D. Ca3(PO4)2
Ksp = 4.0 x 10 -11
36. For which type of titration will the pH be acidic at the
equivalence point?
Strong acid vs. strong base.
Strong acid vs. weak base.
Weak acid vs. strong base.
All of the above.
None...
Which one of these salts will form a basic solution upon dissolving
in water?
A) KBr
B) KClO3
C) LiCl
D) NaNO3
E) NH4NO3
Please explain how you got the answer for my own reference, I
really appreciate it.
Which of the following mixtures will be a buffer when dissolved
in a liter of water?
0.1 mol Ca(OH)2 and 0.3 mol HI
0.3 mol NaCl and 0.3 mol HCl
0.4 mol NH3 and 0.4 mol HCl
0.2 mol HBr and 0.1 mol NaOH
0.2 mol H3PO4 and 0.1 mol NaOH
Which of the following mixtures will be a buffer when dissolved
in a liter of water?
A.
0.3 mol NaCl and 0.3 mol HCl
B.
0.1 mol Ca(OH)2 and 0.3 mol HI
C.
0.2 mol HBr and 0.1 mol NaOH
D.
0.4 mol NH3 and 0.4 mol HCl
E.
0.2 mol H3PO4 and 0.1 mol NaOH
Which of the following salts would be more soluble in acid
solution than in pure water?
PbBr2
AgNO3
SrCl2
AgI
Please provide a thorough explanation as I was absent during
this lecture... Thank you!!