In: Statistics and Probability
One state lottery has 1,000 prizes of $1; 130 prizes of $10; 20 prizes of $55; 5 prizes of $300; 2 prizes of $1,010; and 1 prize of $2,500. Assume that 31,000 lottery tickets are issued and sold $1
What is the lottery's expected profit per ticket?
What is the lottery's standard deviation of profit per ticket?
1,000 prizes of $1;
130 prizes of $10;
20 prizes of $55;
5 prizes of $300;
2 prizes of $1,010;
1 prize of $2,500
1,000 prizes of $1; 130 prizes of $10; 20 prizes of $55; 5 prizes of $300; 2 prizes of $1,010; and 1 prize of $2,500
No. of prizes f(i) | Amount in $ (xi) |
1000 | 1 |
130 | 10 |
20 | 55 |
5 | 300 |
2 | 1010 |
1 | 2500 |
Assume that 31,000 lottery tickets are issued and sold $1
Thus , The lottery makes $31,000 on sales.
Its pay out is given by - No . of prizes * Amount of prize
No. of ticket f(i) | Prize in $ (xi) | xi*fi |
1000 | 1 | 1000 |
130 | 10 | 1300 |
20 | 55 | 1100 |
5 | 300 | 1500 |
2 | 1010 | 2020 |
1 | 2500 | 2500 |
It pays out = 1000+1300+1100+1500+2020+2500 = 9420
It pays out = 9420
Total 31,000 lottery tickets are issued and sold $1
Ticket sold without giving any prizes ( i.e prize =0 ) = 31,000 - (1000+130 + 20 + 5 + 2 + 1)
= 29842
Prizes in $ (xi) | No. of ticket f(i) | |
0 | 29842 | |
1 | 1000 | |
10 | 130 | |
55 | 20 | |
300 | 5 | |
1010 | 2 | |
2500 | 1 |
We find Probability of each Prize value tickets P(x) = No. of ticket f(i) / 31,000
Let us define a variable X = Prize of ticket - selling price of each ticket ($1 )
= xi - 1
Prizes in $ (xi) | No. of ticket f(i) | X=winnig | P(x) | P(x)*X |
0 | 29842 | -1 | 0.962645 | -0.96265 |
1 | 1000 | 0 | 0.032258 | 0 |
10 | 130 | 9 | 0.004194 | 0.037742 |
55 | 20 | 54 | 0.000645 | 0.034839 |
300 | 5 | 299 | 0.000161 | 0.048226 |
1010 | 2 | 1009 | 6.45E-05 | 0.065097 |
2500 | 1 | 2499 | 3.23E-05 | 0.080613 |
Total | 31000 | 3869 | 1 | -0.69613 |
Thus lottery's expected profit per ticket is given by = - P(x)*X = - (-0.69613)
Lottery's expected profit per ticket = 0.69613
{ we have taken negative sign in (- P(x)*X ) because we defined variable X as Prize of ticket - 1 }
Total Profit = expected profit per ticket * Total Number of tickets sold = 0.69613 * 31000 = 21580
= $ 21,580
Now to find lottery's standard deviation of profit per ticket
Standard deviation =
Now = P(x)*(X - Mean(X) )2
Here Mean of X = E(X) = 0.69613
X=winnig | P(x) | P(x)*X | (X-E(X)) 2*P(x) |
-1 | 0.962645 | -0.96265 | 2.769391985 |
0 | 0.032258 | 0 | 0.015632129 |
9 | 0.004194 | 0.037742 | 0.289194154 |
54 | 0.000645 | 0.034839 | 1.832640149 |
299 | 0.000161 | 0.048226 | 14.32661702 |
1009 | 6.45E-05 | 0.065097 | 65.57564678 |
2499 | 3.23E-05 | 0.080613 | 201.6011679 |
3869 | 1 | -0.69613 | Total =286.4102901 |
Thus Var(X) =sum ( ( X- E(X) ) 2*P(x) )
=286.4102901
Hence , lottery's standard deviation of profit per ticket =
= 16.92366
And lottery's expected profit per ticket is 0.69613
And total profit is $ 21,580