Use the following to answer all of the questions. According to the Pew Internet and American...

Use the following to answer all of the questions. According to the Pew Internet and American Life Project 75% of American adults use the Internet. A survey of 600 adults aged 50-64 found 420 used the Internet (70%). We want to determine whether the proportion of Internet users age 50-64 differs from the overall proportion of 0.75. 1.What is the alternative hypothesis?

2. Compute the test statistic. Give answer to two decimal places.

3. Compute the p-value. Round answer to four decimal places.

4. If a=.05, what is the conclusion to the test? Reject Ho or Do not Reject Ho

Solutions

Expert Solution

The provided details are:

n=600 sample size, no of favorable condition X=420 hence sample proportion is :

The Hypotheses are:

Based on the given hypothesis it will be a two-tailed Z test

1) The test statistic:

2) P-value :

P-value is computed using the Z table or excel tool as:

P-value=0.0047

3) Rejection region:

At 0.05 level of significance reject Ho if |Z| >Z _0.025 =1.96 Computed using the Z table shown below with illustration.

Conclusion:

Since P-value <0.05 hence we reject the Null hypothesis and conclude that there is sufficient evidence to support the claim.

Z table:

orchestra answered 1 year ago

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