In: Statistics and Probability
The following data represent samples that were taken on 10 separate days. Each day has a varying sample size and the number of defects for the items sampled is listed. We want to see if this process is consistent and in control.
Day |
Sample Size |
Defects |
1 |
100 |
6 |
2 |
110 |
4 |
3 |
190 |
10 |
4 |
190 |
7 |
5 |
240 |
15 |
6 |
255 |
8 |
7 |
105 |
3 |
8 |
175 |
6 |
9 |
245 |
22 |
10 |
265 |
27 |
a. Find the UCL.
b. Find the LCL.
c. Is the process in control? Why/why not?
Answer:-
Given That:-
The data represent samples that were taken on 10 separate days. Each day has a varying sample size and the number of defects for the items sampled is listed. We want to see if this process is consistent and in control.
Form given data
* The following data representation Samples that were taken on 10 separate days.
* Each day has a varying sample size and the number of defects for the items sampled is listed.
* We will use P chart (control for Proportion) to check for process in constant or not.
Day | Sample Size | Defects | Proportion of defects for 10 separate days. |
1 | 100 | 6 | 6/100 = 0.062 |
2 | 110 | 4 | 4/110 = 0.036 |
3 | 190 | 10 | 10/190 = 0.052 |
4 | 190 | 7 | 7/190 = 0.036 |
5 | 240 | 15 | 15/240 = 0.062 |
6 | 255 | 8 | 8/255 = 0.031 |
7 | 105 | 3 | 3/105 = 0.028 |
8 | 175 | 6 | 6/175 = 0.034 |
9 | 245 | 22 | 22/245 = 0.089 |
10 | 265 | 27 | 27/265 = 0.101 |
* Center line, = 0.533/10
= 0.0533
Standard deviation of
=
=
sd(P) = 0.7103
(a)
Find the UCL:
UCL = P + 3 * sd(P) = 0.0533 + 3*0.7103
= 2.1842
UCL = 2.1842
(b)
Find the LCL:
LCL = P - 3 * sd(P) = 0.0533 - 3*0.7103 = -2.0776
LCL = 0 [The Proportion cannot be negative value]
(c)
Is the process in control? Why/why not
As all the sample Proportion of defectives are between LCL and UCL the process is in control.