In: Operations Management
Twenty samples with 100 units each were taken; with the following number of defectives in each respective sample: 11, 2, 7, 5, 6, 7, 8, 5, 3, 6, 4, 3, 5, 6, 2, 5, 0, 9, 10, and 8.
Answer:
Answer a.
Plot the number of samples, Defective units in each sample out of 100 units in each sample.
Calculate the proportion (p%) for each sample using below formula
p% = (Defective units / No. of units in each sample)*100
Samples |
Defective units |
No. of units in each sample |
p |
|
1 |
11 |
100 |
0.110 |
|
2 |
2 |
100 |
0.020 |
|
3 |
7 |
100 |
0.070 |
|
4 |
5 |
100 |
0.050 |
|
5 |
6 |
100 |
0.060 |
|
6 |
7 |
100 |
0.070 |
|
7 |
8 |
100 |
0.080 |
|
8 |
5 |
100 |
0.050 |
|
9 |
3 |
100 |
0.030 |
|
10 |
6 |
100 |
0.060 |
|
11 |
4 |
100 |
0.040 |
|
12 |
3 |
100 |
0.030 |
|
13 |
5 |
100 |
0.050 |
|
14 |
6 |
100 |
0.060 |
|
15 |
2 |
100 |
0.020 |
|
16 |
5 |
100 |
0.050 |
|
17 |
0 |
100 |
0.000 |
|
18 |
9 |
100 |
0.090 |
|
19 |
10 |
100 |
0.100 |
|
20 |
8 |
100 |
0.080 |
|
Average of all 20 observations p% (p bar) or Central Line |
0.056 |
5.60% |
Central Line = CL = p bar = Average of all 20 observations p% = 0.056
Sample size (n) = |
100 |
p bar = |
0.056 |
z= no. of standard deviation from process average as it is to be calculated for 3σ |
3 |
Standard Deviation (σ) = √[p bar * (1- p bar)]/n
σ = √[0.056 * (1- 0.056)]/100
σ = 0.0230
UCL (Upper Control Limit) = p bar+3σ = 0.056 + (3*0.0230) = 0.1250
LCL (Lower Control Limit) = p bar-3σ = 0.056 - (3*0.0230) = -0.0130
Answer b.
Make following table in Excel:
STEPS
In Excel, use following graph:
Select all data of the above table.
Click on “Insert” tab and then “Line”
Following chart will appear:
Answer c.
The process is stable for quality control purposes as it well within the UCL & LCL.
For getting the above chart use following steps:
STEPS
In Excel, use following graph:
Select all data of the above table.
Click on “Insert” tab and then “Line”