Question

In: Chemistry

Given the enthalpies of reaction: 2P(g) + 3Cl2(g) → 2PCl3(g) DH = –574 kJ 2P(g) +...

Given the enthalpies of reaction: 2P(g) + 3Cl2(g) → 2PCl3(g) DH = –574 kJ 2P(g) + 5Cl2(g) → 2PCl5(g) DH = –887 kJ What is the enthalpy change of the following reaction: PCl3(g) + Cl2(g) → PCl5(g)

Question 5 options:
1461 kJ
–1461 kJ
222 kJ
–313 kJ
–156 kJ

Solutions

Expert Solution

2P(g) + 3Cl2(g) → 2PCl3(g)    DH = –574 kJ

2P(g) + 5Cl2(g) → 2PCl5(g)    DH = –887 kJ

(-)        (-)                (-)                         (+)

------------------------------------------------------------------

2PCl5(g) -----------> 2PCl3(g) + 2Cl2(g)    DH = 313KJ

PCl5(g) -----------> PCl3(g) + Cl2(g)    DH = 313/2    = 156.5KJ

PCl3(g) + Cl2(g) ---------------> PCl5(g)   DH = -156.5KJ >>>>>answer

–156 kJ >>>>answer


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