Question

1. Categorize these measurements associated with student life according to level: nominal, ordinal, interval, or ratio.

1 (a) Length of time to complete a test

a)nominal

b)ordinal     

c)interval

d) ratio

1(b) Time of first class

a) nominal

b) ordinal     

c) interval

d) ratio

1(c) Major field of study

a) nominal

b) ordinal    

c) interval

d) ratio

1(d) Course evaluation scale: poor, acceptable, good

a) nominal

b) ordinal    

c) interval

d) ratio

1(e) Score on last test (based on 100 possible points)

a) nominal

b) ordinal    

c) interval

d) ratio

1(f) Age of student

a) nominal

b) ordinal    

c) interval

d)ratio

2. Assume that x has a normal distribution with the specified mean and standard deviation. Find the indicated probability. (Enter a number. Round your answer to four decimal places.)

μ = 20; σ = 4.2

P(x ≥ 30) = ______

3. Compute P_5,4. (Enter an exact number.) =______

Answer 1

(a) ratio

Reason : Since this a quantitative variable and true zero exists, which means someone who rook 60 minutes is twice as much as someone who took 30 minutes. we say it is ratio test.

(b) interval

Reason : Since rhe variable is in intervals of time, the measure is interval

(c) nominal

Reason : Since the variable is qualitative and there is no order or ranking of variable it is nominal data.

(d) ordinal

Reason : Since the variable is qualitative and there is exists ranking of variable, it is ordinal data.

(e) ratio

Reason : Since this a quantitative variable and true zero exists, we say it is ratio test.

(f) ratio

Reason : Since this a quantitative variable and true zero exists, we say it is ratio test.

2.

We know that,

z = (30 - 20)/4.2

z = 2.3809

P(z ≥ 2.3809) = 1 - P(z ≥ 2.3809)

= 1 - 0.9914

= 0.0086

3.

P(5,4) = (5*4*3*2*1)/(1)

= 120