Question

What is the empirical formula for 9.48 of na, 1.66 of c, 1.9 of n

Answer 1

9.48 of Na, 1.66 of C, 1.9 of N are taken has Na, C, N

Element           wt            A.wt            relative number        simple ratio

Na              9.48             23               9.48/23 = 0.412           0.412/0.136 = 3

C                1.66            12                1.66/12   = 0.138      0.138/0.136    = 1

N                1.9              14                  1.9/14   = 0.135        0.136/0.136 = 1

   The empirical formula   Na3CN