Question
In: Chemistry
A 100.0 mL sample of 0.10 M NH3 is titrated with 0.10 M HNO3. Determine the...
A 100.0 mL sample of 0.10 M NH3 is titrated with 0.10 M HNO3. Determine the pH of the solution after the addition of 50.0 mL of HNO3. The Kb of NH3 is 1.8 × 10-5.
Solutions
Expert Solution
no of moles of NH3 = molarity * volume in L
= 0.1*0.1 = 0.01 moles
no of moles of HNO3 = molarity * volume in L
= 0.1*0.05 = 0.005 moles
NH3 + HNO3 ---------------> NH4NO3
I 0.01 0.005 0
C -0.005 -0.005 0.005
E 0.005 0 0.005
Kb = 1.8*10^-5
PKb = -logKb = -log1.8*10^-5 = 4.75
POH = PKb + log[NH4NO3]/[NH3]
= 4.75 + log0.005/0.005
= 4.75 +0
= 4.75
PH = 14-POH
= 14-4.75 = 9.25
queen_honey_blossom answered 1 year agoRelated Solutions
A 100.0 mL sample of 0.10 M NH3 is titrated with 0.10 M HNO3. Determine the...
A 100.0 mL sample of 0.10 M NH3 is titrated with 0.10 M HNO3.
Determine the pH of the solution after the addition of 50.0 mL of
HNO3. The Kb of NH3 is 1.8 × 10-5.
1. A 100.0 mL sample of 0.10 M NH3 is titrated with 0.10 M HNO3. Kb,...
1. A 100.0 mL sample of 0.10 M NH3 is titrated with 0.10 M HNO3.
Kb, NH3 = 1.8 × 10−5. Determine the pH of the solution at each of
the following points in the titration:
(a) before addition of any HNO3
(b) after the addition of 50.0 mL HNO3
(c) after the addition of 75.0 mL HNO3
(d) at the equivalence point
(e) after the addition of 150.0 mL HNO3
2. (12 points) Consider the titration of 37.0 mL...
Q4, A 100.0mL sample of 0.10 M NH3 is titrated with 0.10 M HNO3 Determine the...
Q4, A 100.0mL sample of 0.10 M NH3 is titrated with
0.10 M HNO3 Determine the pH of the
solution after addition of 100ml of HNO3
The kb of NH3 is 1.8x10-5
A 100.0 mL sample of 0.20 M HF is titrated with 0.10 M KOH. Determine the...
A 100.0 mL sample of 0.20 M HF is titrated with 0.10 M KOH.
Determine the pH of the solution after the addition of 200.0 mL of
KOH. The Ka of HF is 3.5 × 10-4.
Answer: 8.14 but how do I get this?? I'm so lost!
A 100.0 mL sample of 0.20 M HF is titrated with 0.20 M KOH. Determine the...
A 100.0 mL sample of 0.20 M HF is titrated with 0.20 M KOH.
Determine the pH of the solution after the addition of 50.0 mL of
KOH. The Ka of HF is 3.5 × 10-4.
A. 2.08
B. 3.15
C. 4.33
D. 3.46
E. 4.15
Consider the following four titrations. i. 100.0 mL of 0.10 M HCl titrated by 0.10 M...
Consider the following four titrations.
i. 100.0 mL of 0.10 M HCl titrated by 0.10 M
NaOH
ii. 100.0 mL of 0.10 M NaOH titrated by 0.10 M
HCl iii. 100.0 mL of 0.10 M CH3NH2 titrated by 0.10
M HCl
iv. 100.0 mL of 0.10 M HF titrated by 0.10 M
NaOH Rank the titrations in order of:
increasing volume of titrant added to reach the equiva-
lence point.
increasing pH initially before any titrant has been added.
increasing...
5) A 100.0 mL sample of 0.18 M HClO4 is titrated with 0.27 M LiOH. Determine...
5) A 100.0 mL sample of 0.18 M HClO4 is titrated with 0.27 M
LiOH. Determine the pH of the solution
a) before the addition of any LiOH.
b) after the addition of 30.0 mL of LiOH.
c) after the addition of 50.0 mL of LiOH.
d) after the addition of 66.67 mL of LiOH (this is the
equivalence point).
e) after the addition of 75.0 mL of LiOH.
A 35.0 mL sample of 0.150 M ammonia (NH3, Kb=1.8×10−5) is titrated with 0.150 M HNO3....
A 35.0 mL sample of 0.150 M ammonia (NH3, Kb=1.8×10−5) is
titrated with 0.150 M HNO3. Calculate the pH after the addition of
each of the following volumes of acid. Express your answer
using two decimal places.
A. 0.0 mL
B. 17.5 mL
C. 35.0 mL
D. 80.0 mL
A 100.0 mL sample of 0.100 M methylamine (CH3NH2;Kb=3.7×10−4) is titrated with 0.250 M HNO3. Calculate...
A 100.0 mL sample of 0.100 M methylamine
(CH3NH2;Kb=3.7×10−4) is titrated with 0.250 M
HNO3. Calculate the pH after the addition of each of the following
volumes of acid.
Part A: 0.0 mL
Part B: 20.0 mL
Part C: 40.0 mL
Part D: 60.0 mL
A student reacted 100.0 mL of 0.9800 M HCl with 100.0 mL of 0.9900 M NH3....
A student reacted 100.0 mL of 0.9800 M HCl with 100.0 mL of
0.9900 M NH3. The density of
the reaction mixture was 1.02 g/mL and the heat capacity was 4.016
J/g K.
Calculate the enthalpy of neutralization by plotting and using the
data shown below.
Time(min) Temp(oC)
0.0 23.25
0.5 23.27
1.0 23.28
1.5 23.30
2.0 23.30
3.0 23.35
4.0 23.44
4.5 23.47
mix ---------
5.5 28.75...
ADVERTISEMENT
ADVERTISEMENT
Latest Questions
- Explain the four categories of proactive internationalization motives by John Dunning (1993),
- North Platt Machinery Company manufactures a shaft that must fit inside a sleeve. The firm has...
- Watch 3 commercials. Identify the organizational pattern, reasoning and appeals used. P/s: Any commercials
- Consider a standing person in the center of a large room. Approximate the person as a...
- 2. Island Water Sports is a business that provides rental equipment and instruction for a variety...
- A ring of charge with radius 1.5 cm and a charge of 100nC has the electric...
- A direct titration of .68311 grams sample of diprotic acid (H2X) requires 37.45 ml of 0.1372M...
ADVERTISEMENT