Question

A psychologist wanted to know if students in her class were more likely to cheat if they were low achievers. She divided her 60 students into three groups (low, middle, and high) based on their mean course-testings score on the previous three tests. She then asked them to rate how likely they were to cheat on a course-testings if the opportunity presented itself with very limited chance for consequences. The students rated their desire to cheat on a scale ranging from 1-100, with lower numbers indicating less desire to cheat.

4. Conduct a one-way ANOVA. Report your statistical findings (including any applicable tables in APA format) here.

Achievement_Group	Gender	Cheat
1	0	20
1	0	40
1	0	49
1	0	50
1	0	51
1	0	51
1	0	52
1	0	53
1	0	58
1	1	42
1	1	48
1	1	48
1	1	52
1	1	55
1	1	55
1	1	56
1	1	59
1	1	67
1	1	80
1	1	79
2	0	19
2	0	25
2	0	20
2	0	29
2	0	24
2	0	32
2	0	25
2	0	27
2	0	30
2	0	55
2	1	40
2	1	25
2	1	27
2	1	35
2	1	42
2	1	30
2	1	30
2	1	34
2	1	40
2	0	27
3	0	60
3	0	65
3	0	69
3	0	78
3	0	79
3	0	80
3	0	80
3	0	90
3	0	95
3	0	50
3	1	55
3	1	55
3	1	60
3	1	69
3	1	70
3	1	70
3	1	88
3	1	90
3	1	90
3	1	91

Answer 1

Solution

We will solve it using excel

The output from excel for anova is given below

Anova: Single Factor
SUMMARY
Groups	Count	Sum	Average	Variance
Achievement_Group	60.0000	120.0000	2.0000	0.6780
Gender	60.0000	30.0000	0.5000	0.2542
Cheat	60.0000	3165.0000	52.7500	457.7161
ANOVA
Source of Variation	SS	df	MS	F	P-value	F crit
Between Groups	106157.5000	2.0000	53078.7500	347.1860	0.0000	3.0470
Within Groups	27060.2500	177.0000	152.8828
Total	133217.7500	179.0000

Define Null and alternative hypothesis

Ho : Three groups (low, middle, and high) have same mean.

H1 : At least one of the group have different mean than other

F statistic = 347.1860

F crit = 3.0470

Decision : F statistic = 347.1860 > F crit = 3.0470 , so reject Ho at 0.05 level of significance.

Conclusion : The mean of doing cheating is different for at least one of the group.