Express the equilibrium constant for the following reaction. 10PCl5(g) ↔ 10PCl3(g) + 10Cl2(g)

Express the equilibrium constant for the following reaction.

10PCl5(g) ↔ 10PCl3(g) + 10Cl2(g)

Solutions

Expert Solution

10PCl5(g) ↔ 10PCl3(g) + 10Cl2(g)

rate of forward reaction = Kf[PCl5]¹⁰

rate of back ward reaction = Kb[PCl3]¹⁰ [Cl2]¹⁰

at equilibrium

rate of forward reaction = rate of back ward reaction

Kf[PCl5]¹⁰ = Kb[PCl3]¹⁰ [Cl2]¹⁰

Kf/Kb = [PCl3]¹⁰ [Cl2]¹⁰/[PCl5]¹⁰

Kc = [PCl3]¹⁰ [Cl2]¹⁰/[PCl5]¹⁰

queen_honey_blossom answered 1 year ago

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