Question

1. What Celsius temperature, T 2 , is required to change the volume of the gas sample in Part A ( T 1 = 45 ∘ C , V 1 = 1480 L ) to a volume of 2960 L ? Assume no change in pressure or the amount of gas in the balloon.

2. An air bubble has a volume of 0.490 L at 18 ∘C .

What is the volume, in liters, at 6 ∘C , if n and P do not change?

What is the volume, in liters, at 426 K , if n and P do not change?

What is the volume, in liters, at -13 ∘C , if n and P do not change?

What is the volume, in liters, at 572 K , if n and P do not change?

Answer 1

1)

Given:

Ti = 45.0 oC

= (45.0+273) K

= 318 K

Vi = 1480 L

Vf = 2960 L

use:

Vi/Ti = Vf/Tf

1480 L / 318.0 K = 2960 L / Tf

Tf = 636 K

Tf = (636-273) oC

Tf = 363 oC

Answer: 363 oC

2)

a)

Given:

Vi = 0.490 L

Ti = 18.0 oC

= (18.0+273) K

= 291 K

Tf = 6.0 oC

= (6.0+273) K

= 279 K

use:

Vi/Ti = Vf/Tf

0.490 L / 291.0 K = Vf / 279.0 K

Vf = 0.470 L

Answer: 0.470 L

b)

Tf = 426.0 K

use:

Vi/Ti = Vf/Tf

0.490 L / 291.0 K = Vf / 426 K

Vf = 0.717 L

Answer: 0.717 L

c)

Tf = -13.0 oC

= (-13.0+273) K

= 260 K

use:

Vi/Ti = Vf/Tf

0.490 L / 291.0 K = Vf / 260.0 K

Vf = 0.438 L

Answer: 0.438 L

d)

Tf = 572 K

use:

Vi/Ti = Vf/Tf

0.490 L / 291.0 K = Vf / 572 K

Vf = 0.963 L

Answer: 0.963 L