Question
In: Physics
A 25-gram block is resting on a horizontal, frictionless surface and is attached to a horizontal...
A 25-gram block is resting on a horizontal, frictionless surface and is attached to a horizontal spring of k = 210 N/m. The spring is stretched so that the block is 27 cm away from the spring’s equilibrium position and released from rest.
a) What is the velocity of the block when it passes through the equilibrium point?
b) At what distance from equilibrium is the spring’s potential energy equal to the block’s kinetic energy?
c) Suppose the block has a speed of 21 m/s when it passes through the equilibrium point for the first time, how much work is done by the force of kinetic friction during that first part of the block’s motion?
Solutions
genius_generous answered 1 year agoRelated Solutions
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