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In: Physics

Group Work 3 – GI Joe (option 2) G. I. Joe paratrooper Ripcord (80 kg) is...

Group Work 3 – GI Joe (option 2)

G. I. Joe paratrooper Ripcord (80 kg) is invading Cobra HQ. He’s brought in by a stealth bomber, where he jumps from an altitude of 10,000 ft (approx 3000 meters).

What is his initial acceleration?

If the chute failed, what would his average acceleration be over the trip? Assuming the average acceleration, how fast would he hit the ground?

Derive an equation for the ratio of terminal velocities between diving head first vs. spread eagle (lying flat).

At 1,000 ft, he pulls the parachute cord (a 1m x 5m rectangular chute). What is his initial acceleration due to drag?

How long does it take to reach the ground at Cobra HQ if the parachute opens at 1,000 ft?

Expert Solution

Initial acceleration would be, g=32ft/s².

If chute fails, let us consider that there is no drag force acting in his fall.

in that case velocity at which he hits ground would be, v= = = 800ft/s

Now considering coefficient of drag C_dh & C_de for head dive & spread eagle type of fall. & projected .areas are A_h & A_e respectively

we know terminal velocity =

therefore taking ratios of terminal velocities it will be V_h/V_e =

At altitude of 1000ft, velocity will be = 759 ft/s. = 231.3m/s

we know, drag due to parachute as

=> once substituted we get drag force as 0.5*1.225*231.3² * (1*5)*1.28 = 62915.6N

thus acceleration due to drag will be F/m = 62915.6/80 = 786.44m/s²

Therefore, net deceleration is 786.44-9.81m/s ² = 776.64m/s²

genius_generous answered 1 year ago

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