In: Finance
A bank lends a CHF 1’000’000 loan at an annual interest rate of 4% to a customer. The loan foresees a complete linear repayment over its term of 5 years. Debt servicing is made once a year in arrear.
Calculate the installment payment and the interest payment at the end of the third year.
Installment Payment at the end of third year is $ 224,627.11
Interest Payment at the end of third year is $ 24,934.43
Step-1:Calculation of annual payment | ||||||
Annual Payment | =-pmt(rate,nper,pv,fv) | Where, | ||||
= $ 224,627.11 | rate | = | 4% | |||
nper | = | 5 | ||||
pv | = | $ 1,000,000 | ||||
fv | = | 0 | ||||
Step-2:Calculation of loan repayment schedule | ||||||
Year | Beginning Loan | Annual Payment | Interest Expense | Principal Repayment | Ending Loan Value | |
a | b | c=a*4% | d=b-c | e=a-d | ||
1 | $ 10,00,000.00 | $ 2,24,627.11 | $ 40,000.00 | $ 1,84,627.11 | $ 8,15,372.89 | |
2 | $ 8,15,372.89 | $ 2,24,627.11 | $ 32,614.92 | $ 1,92,012.20 | $ 6,23,360.69 | |
3 | $ 6,23,360.69 | $ 2,24,627.11 | $ 24,934.43 | $ 1,99,692.69 | $ 4,23,668.00 | |
4 | $ 4,23,668.00 | $ 2,24,627.11 | $ 16,946.72 | $ 2,07,680.39 | $ 2,15,987.61 | |
5 | $ 2,15,987.61 | $ 2,24,627.11 | $ 8,639.50 | $ 2,15,987.61 | $ 0.00 | |
Note: | ||||||
Debt servicing is made once a year in arrear. | ||||||
It means payment are made at the end of year. | ||||||