Question

In: Electrical Engineering

• Building Size: 3,800 square feet (exclusive of an unfinished basement, not adaptable for future use,...

• Building Size: 3,800 square feet (exclusive of an unfinished basement, not adaptable for future use, an unfinished attic, and open porches)

• Small Appliance Branch Circuits: 3

• Laundry Branch Circuits: 1

• Fastened-in-Place Appliances: Water heater (28 kVA), Dishwasher (1,200 VA), Food Disposal (1,200 VA), Attic Fans (2) @ 750 VA (1,500 VA total)

• Clothes Dryer: 5 kW

• Ranges, Ovens, Cooktops: Range 12 kW

• HVAC System: 3.5 Ton AC system 240 V, 17.9 A, Air handler 3.3 A

2. What is the total fixed-in-place appliance load? Show all calculations.

Solutions

Expert Solution

1) here dwelling lighting load is based on the 3VA/sq.ft.

so total load lighting load= 3 X 3800 = 11400 VA---------------(1)

2)here we have 3 small branch circuit and if they are of 1500 VA. then total load of them will be

so load of branch circuit = 3 X 1500 = 4500 VA----------------(2)

3) If laundary branch circuit is of 1500 VA then

load of laundry circuit = 1500 VA----------------------------------(3)

4) Fastened fixed appliances load

water heater load = 28 kVA = 28000 VA----------------------(4)

Dishwasher load = 1200 VA--------------------------------(5)

Food disposal load = 1200 VA-----------------------(6)

Attic fans load = 2 X 750 = 1500 VA-----------------(7)

Clothes dryer = 5 kW = 5000 VA --------------------(8)

Ranges,ovens, cooktops load = 12 kW = 12000VA---(9)

HVAC system load = 240 X 17.9 = 4296 VA -----(10)

Air handler load = 240 X 3.3 = 792 VA --------------(11)

So by using above 11 result we can add them and finally we get total load = 71388 VA = 71.388 kVA


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