In: Chemistry
The value of DHfe for Al2O3 (s) is __________ kJ.
The ΔHf of a substance is actually the heat of formation released or absorbed during the reaction. Generally it is calculated for the entire reaction.
Now if we consider the formation of Al2O3 (s), then the formation reaction is-
2 Al(s) + 3 O2(g) ------------------> 2 Al2O3(s)
Now ΔHf for this reaction will be-
ΔHf = net heat of formation of products - net heat of formation of reactants
= Σn(ΔHf)Products − Σn(ΔHf)Reactants
= Hf (2 Al2O3(s)) - [Hf (2 Al(s)) + Hf (3 O2(g)) ]
= 2 * Hf (Al2O3(s)) - 2* Hf (Al(s)) - 3* Hf (O2(g))
Now putting the values form a reference table-
ΔHf = 2 * Hf (Al2O3(s)) - 2* Hf (Al(s)) - 3* Hf (O2(g))
= 2 mols * (−1675.5) - 2* 0 - 3* 0 because heat of formation of naturally available elements = 0
= - 3,351 kJ
So value of ΔHf for Al2O3 (s) is _- 3,351 kJ