Question

In: Chemistry

A buffer solution is formed by mixing 50mL of 0.30M HClO with 300mL of 0.20M NaClo....

A buffer solution is formed by mixing 50mL of 0.30M HClO with 300mL of 0.20M NaClo. The ka for HClO is 2.9 x 10^-8.

1. Write the buffer reaction including states and excluding spectator ions.

2. Calculate the initial concentration of each buffer component.

3. Calculate the pH of the buffer - be sure to include validation if approximations are used.

Expert Solution

1. HClO + NaClO

weak acid and its salt with strong base is called acid buffer solution.

HClO NaClO

M1 = 0.3 M2 = M1 = 0.2M M2=

V1 = 50ml V2 = 50+300 = 350ml V1 = 3000ml V2 = 300+50= 350ml

M1V1 = M2V2 M1V1 = M2V2

M2 = M1V1/V2 = 0.3*50/300 = 0.05M M2 = M1V1/V2 = 0.2*300/350 = 0.1714M

Ka = 2.9*10^-8

PKa = -logKa

= -log2.9*10^-8 = 7.5376

PH = PKa + log[NaClO]/[HClO]

= 7.5376 + log0.1714/0.05

= 7.5376 + 0.5354 = 8.073 >>>>answer

queen_honey_blossom answered 2 years ago

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