In: Statistics and Probability
Is this a binomial distribution? Explain.
Is this a binomial distribution? Explain.
For a binomial distribution, P(X = x) = C[n,x] x px x qn-x
X = 0, P(X = 0) = C[n,0] x p0 x qn = 1 x 1 x qn = 0.064; one likely solution is n = 3 and q = 0.4
Then p = 1-0.4 = 0.6
X = 1, P(X = 1) = C[n,1] x p1 x qn-1 = n x p x qn-1 = 3 x 0.6 x 0.42 = 0.288
X = 2, P(X = 2) = C[n,2] x p2 x qn-2 = n x (n-1) x p2 x qn-2 /2 = 3 x 0.62 x 0.4 = 0.432
X = 3, P(X = 3) = C[n,3] x p3 x qn-3 = 1 x 0.63 x 0.40 = 0.216
We see that these values are matching with the values in the table.
So we can conclude that X follows a binomial distribution.
So we can conclude that X follows a binomial distribution