In: Statistics and Probability
The weights of a certain brand of candies are normally distributed with a mean weight of 0.8617 g and a standard deviation of 0.0517 g. A sample of these candies came from a package containing 440 candies, and the package label stated that the net weight is 375.5 g. (If every package has 440 candies, the mean weight of the candies must exceed StartFraction 375.5 Over 440 EndFraction equals0.8535 g for the net contents to weigh at least 375.5 g.)
Solution :
mean = = 0.8617
standard deviation = = 0.0517
n = 440
= = 0.8617
= / n = 0.0517 / 440 = 0.0025
P( > 0.8535) = 1 - P( < 0.8535)
= 1 - P[( - ) / < (0.8535 - 0.8617) /0.0025 ]
= 1 - P(z < -3.28)
Using z table,
= 1 - 0.0005
= 0.9995