In: Statistics and Probability
The weights of the fish in a certain lake are normally distributed with a mean of 9.4 lb and a standard deviation of 2.3. If 42 fish are randomly selected, what is the probability that the mean weight will be more than 9.7 lb?
Solution :
Given that ,
mean =
= 9.4
standard deviation =
= 2.3
=
/
n = 2.3 /
42 = 0.3549
P(
> 9.7) = 1 - P(
< 9.7 )
= 1 - P[(
-
) /
< (9.7 -9.4)/0.3549 ]
= 1 - P(z < 0.85 )
= 0.8023 , Probability = 0.8023