Under constant temperature, a pressure of 12 torr and a volume of 8 L, what is...

Under constant temperature, a pressure of 12 torr and a volume of 8 L, what is the new pressure if the volume decreased to 6 L?

Keq = [products] / [reactants]. Knowing any two; Keq, product or reactant concentrations, will enable determination of the other?

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Expert Solution

Ans 1:

using the ideal gas law , pV = nRT

pressure is related to Volume by the expression ,

p1V1 = p2V2

where p is pressure in atm and V is volume in L

12 torr = 0.0157895 atm

so putting all the values in the formula

0.0157895 x 8 = p2 x 6

p2 = 0.0210527 atm

or 16 torr

Ans 2 :

Yes when the values of any 2 determinants are known , the value of third unknown can be easily calculated .

For eg if concentrations of reactant and products are known , they can give the value of equillibrium constant .

K = [P] / [R]

Likewise the concentration of product can be determined by multiplying reactant concentration with K

[P] = K [R]

queen_honey_blossom answered 1 year ago

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