In: Biology
Comb shape in chickens results from the epistatic interaction of two genes. The first gene (T/t) affects the basic shape of the comb such that: TT and Tt results in a walnut (normal) comb while tt results in pea comb. The recessive allele (r) of a second gene (R/r) modifies the first gene, but the dominant allele (R) does not. Thus RR and Rr has no effect on comb shape, while rr paired TT or Tt produces a rose comb and rr paired with tt produces a single comb
a. Report the phenotype for each of the genotypes below:
TTRr = _________________________________
TtRR = _________________________________
ttRr = __________________________________
Ttrr = __________________________________
b. A farmer makes the following genetic cross among his chickens: Male = Ttrr x Female = ttRr
What are the phenotypes of the parent chickens?
Report all possible genotypes and phenotypes of offspring.
a)
TTRr =Walnut comb (since RR and Rr has no effect on comb shape)
TtRr = Walnut comb (since RR and Rr has no effect on comb shape)
ttRr = Pea comb ( Since RR and Rr has no effect on comb shape)
Ttrr = Rose comb (since rr affects the comb shape and masks walnut comb)
b)
Genotype of male parent: Ttrr
phenotype of male parent: Rose comb
genotype of female parent: ttRr
phenotype of female parent: Pea comb
Parent cross: Ttrr (male) * ttRr (female)
gametes of male parent: Tr, tr
gametes of female parent: tR, tr
offspring: TtRr (walnut comb), Ttrr (rose comb) ,ttRr (pea comb), ttrr (single comb)
genotypic ratio: 1 (TtRr) :1 (Ttrr) :1(ttRr) :1 (ttrr)
Phenotypic ratio - 1 (walnut comb) : 1 (rose comb) : 1 (pea comb) : 1 (single comb)