In one model of the hydrogen atom, an electron orbits a proton in a circle of...

In one model of the hydrogen atom, an electron orbits a proton in a circle of radius 5.28×10^-11 m with a speed of 2.18×10⁶ m/s. What is the acceleration of the electron in this model?

What is the period of the motion?

Expert Solution

Given that-

v=2.18x10⁶m/s & r=5.28x10^-11m

When electron moves around the proton in circular path then centripetal force acts on it.Direction of this centripetal force is towards the center of circular path.Due to this Centripetal force,an acceleration also produced in the motion of electron towards the center of path and that acceleration is called centripetal acceleration.

Centripetal acceleration is given by-

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Period of motion(T) is given by-

genius_generous answered 1 year ago

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