A bicycle tire is spinning counterclockwise at 3.10 rad/s. During a time period Δt = 2.40...

A bicycle tire is spinning counterclockwise at 3.10 rad/s. During a time period Δt = 2.40 s, the tire is stopped and spun in the opposite (clockwise) direction, also at 3.10 rad/s. Calculate the change in the tire's angular velocity Δω and the tire's average angular acceleration α_av. (Indicate the direction with the signs of your answers.)

(a) the change in the tire's angular velocity Δω (in rad/s)

(b) the tire's average angular acceleration α_av (in rad/s²)

Solutions

Expert Solution

Let us consider the counter clockwise direction as positive and the clockwise direction as negative.

Initial angular velocity of the tire = ₁ = +3.1 rad/s

Final angular velocity of the tire = ₂ = -3.1 rad/s

Time period = t = 2.4 sec

Change in the tire's angular velocity =

= -6.2 rad/s

The negative sign indicates it is directed along the clockwise direction.

Average angular acceleration of the tire = _av

_av = -2.58 rad/s²

The negative sign indicates it is directed along the clockwise direction.

a) Change in the tire's angular velocity = -6.2 rad/s

b) Average angular acceleration of the tire = -2.58 rad/s²

genius_generous answered 1 year ago

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