In: Math
Let α and α² be the two roots of the equation x²+ px+q = 0.
Therfore,now we have α + α² = -p
Taking α common
α(1+α) = -p,
and α³ = q
Now, (α(1+α)³ = (-p)³
α³(1+α)³ = -p³
⇒α³ [1+α³+3α(1+α)]=−p³
⇒q[1+q−3p]=−p³
⇒p³ −(3p−1)q+q² =0, which is the relation between p and q.
Relation between p and q = p3 −(3p−1)q+q2 =0