The surface z = 3x^(2) + (1/6)x^(3) - (1/8)x^(4) - 4y^(2) is intersected by the plane...

The surface z = 3x^(2) + (1/6)x^(3) - (1/8)x^(4) - 4y^(2) is intersected by the plane 2x - y = 1. The resulting intersection is a curve on the surface. Find a set of parametric equations for the line tangent to this curve at the point (1,1,-23/24).

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milcah answered 2 years ago

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Question

The surface z = 3x^(2) + (1/6)x^(3) - (1/8)x^(4) - 4y^(2) is intersected by the plane...

Solutions

Expert Solution

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