In: Chemistry
Quiz
Page 10 of 10
A sample of an unknown metal with a mass of 17.8 grams is heated in boiling water to a temperature of 98.0°C. The piece of metal is transferred to a sample of water with a mass of 15.0 grams at a temperature of 26.0°C. The metal cools to 30.5°C and the water warms up to 30.5°C. Calculate the specific heat of the metal. Use the table of specific heat values to identify the metal.
Options:
copper |
|
aluminum |
|
lead |
|
silver |
|
iron |
Heat lose of metal = Heat gain of water
mct = mct
17.8*C*(98-30.5) = 15*4.184*(30.5-26)
c = 0.235J/g-c0
that metal is silver .It's heat capacity is 0.235J/g-c0