In: Chemistry
Identification of Metal..................Copper......Copper.......Unknown......Unknown
Mass of test tube & metal shot...74.4593g...132.8115g...85.5094g.....61.018g
Mass of test tube........................32.0003g.....32.003g.....32.003g.........32.003g
Mass of the metal sample..........42.4562g.....100.8085g...53.5064g.....29.015g
Mass of the set-up......................3.2639g.......3.2639g.......3.2639g.......3.2639g
Mass of set-up&water.............101.7857g....100.9825g...99.5694g....100.7855g
Mass of water in calorimeter.......98.5218g......97.7186g....96.3055g....97.5216g
Initial temperature of metal sample...100C......100C..........100C............100C
Initial temperature of water..........23.55C..........25.29C........24.3213C....24.73C
Final temperature of water and metal25.55C....31.75C.......27.8417C....27.83C
ΔTwater........................................2C..................6.46C.........3.52C..........3.1C
ΔTmetal ....................................-74.85C............-68.25........27.8417C....27.83C
Specific Heat of water............................4.184J/gC.....................................
Heat energy gained by the water .....?....................?.................?.................?
Heat lost by the metal.......................?....................?.................?.................?
Calculated Specific heat...................?....................?.................?.................?
Average Specific heat ............................................?.....................................?
Actual Specific Heat of metal..................................0.385..............................?
% error....................................................................?......................................?
Show your calculations for determining the specific heat of all trials
For trial 1:
Heat energy gained by the water=msdT = 98.5218 g * 4.184J/gC * 2 C = 824.43 J
Heat lost by the metal = msdT = 42.4562 g * smetal * 74.85 C
Calculated Specific heat = smetal = (824.43 J)/( 42.4562 g * 74.85 C) = 0.26 J/gC [as heat lost by metal=heat gained by water]
For trial 2:
Heat energy gained by the water=msdT = 97.7186 g* 4.184J/gC * 6.46 C = 2641.2 J
Heat lost by the metal = msdT = 100.8085 g* smetal * 68.25 C
Calculated Specific heat = smetal = (2641.2 J)/( 100.8085 g * 68.25 C) = 0.384 J/gC
Average Specific heat = 0.26 + 0.384/2 = 0.322 J/gC
% error = (0.385-0.322/0.385) * 100 = 16.4%
For trial 3:
Heat energy gained by the water=msdT = 96.3055 g* 4.184J/gC * 3.52 C = 1418.35 J
Heat lost by the metal = msdT = 53.5064 g* smetal * 27.8417 C
Calculated Specific heat = smetal = (1418.35 J)/( 53.5064 g * 27.8417 C) = 0.952 J/gC
For trial 4:
Heat energy gained by the water=msdT = 97.5216 g* 4.184J/gC * 3.1 C = 1264.89 J
Heat lost by the metal = msdT = 29.015 g* smetal * 27.83 C
Calculated Specific heat = smetal = (1264.89 J)/( 29.015 g * 27.83 C) = 1.566 J/gC
Average Specific heat = 0.952 + 1.566/2 = 1.259 J/gC