A 3-D force vector has the following components: Fx= -30 N Fy= -20N Fz= 50 N...

A 3-D force vector has the following components:

F_x= -30 N F_y= -20N F_z= 50 N

Determine the magnitude and direction angles (angles with the x, y, and z axes) of this vector

Expert Solution

magnitude = sqrt ((-30)^2 + (-20)^2 + 50^2) = 61.64N

angle with x axis = tan(theta) = Fy/Fx = -20/-30 = 2/3 therefore theta_x = 21.14 degree

angle with y axis = tan(theta) = Fz/Fy = 50/-20 = -2.5 therefore theta_y = -68.19 degree

angle with z axis = tan(theta) = Fx/Fz = -30/50 = -3/5 therefore theta_z = -30.96 degree

genius_generous answered 2 years ago

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