Question

1. Using the equation for the Hardy-Weinberg Equilibrium, calculate the following for p=0.7 and q=0.3 and enter in the ratios for the following values.
a. homozygous dominants

b. homozygous recessives|

c. heterozygotes

d. dominant phenotype

2.

Blank 1: Which kind of selection, directional, stabilizing, or disruptive, occurred when beads representing homozygous recessives were removed in the evolution lab?

Blank 2: What kind of selective agent or selective pressure could this activity have imitated?

Question 4 options:

Blank # 1
Blank # 2

Thank you for your time and help.

Answer 1

Question 1);

To calculate the value of Hardy Weinberg frequencies fit different phenotype, the formula is simple :-

p2 + 2pq + q2

In this p is for Homozygous dominant, q is for Homozygous recessive while 2pq is for Heterozygous.

We have been given value of p and q as :- p = 0.7 and q = 0.3

a) Homozygous Dominant

(0.7)2 = 0.49

b) Homozygous recessive

(0.3)2 = 0.09

c) Heterozygotes

2 * 0.7 * 0.3 = 0.42

d) Dominant phenotype

Both Heterozygous and Homozygous Dominant will show the dominant phenotype. So it will be the sum of the frequency of both.

0.49 + 0.42 = 0.91

Question 2:-

In the question, one type of phenotype (Homozygous recessive) is completely removed. During evolution and selection, if only one phenotype is removed while other phenotype is selected, it is called Directional Selection

So the answer for the 1st blank is Directional Selection

This type of selection can happen due to many reasons but the most common reason is Predation. Predators may be able to catch only one type of phenotypic prey (Can be due to many reasons like camouflage, mimicry of the other phenotype)

So the selective agent can be Predators while pressure is Predation.