Question

In: Statistics and Probability

Allergic reactions to poison ivy can be miserable. Plant oils cause the reaction. Researchers at Allergy...

Allergic reactions to poison ivy can be miserable. Plant oils cause the reaction. Researchers at Allergy Institute did a study to determine the effects of washing the oil off within 5 minutes of exposure. A random sample of 1000 people with known allergies to poison ivy participated in the study. Oil from the poison ivy plant was rubbed on a patch of skin. For 500 of the subjects, it was washed off within 5 minutes. For the other 500 subjects, the oil was washed off after 5 minutes. The results are summarized in the following table.

Reaction Within 5 Minutes After 5 Minutes Row Total
None 396 50 446
Mild 61 327 388
Strong 43 123 166
Column Total 500 500 1000

Let's use the following notation for the various events: W = washing oil off within 5 minutes, A = washing oil off after 5 minutes, N = no reaction, M = mild reaction, S = strong reaction. Find the following probabilities for a person selected at random from this sample of 1000 subjects. (Use 3 decimal places.)

1. P(N)=

P(M)=

P(S)=

2. P(N | W)=

P(S | W)=

3. P(N | A)=

P(S | A)=

4. P(N and W)=

P(M and W)=

P(N or M)=

Solutions

Expert Solution

Solution(1a)
We need to calculate P(N) = ?
Here N is No reaction
P(N). can be calculated as
P(N) = Total number of No reaction / Total No. of sample = 446/1000 = 0.446
So there is 44.6% probability that that is no reaction
Solution(1b)
We need to calculate P(M) = ?
Here M is Mild reaction
P(M) can be calculated as
P(M) = Total number of Mild reaction / Total No. of sample = 388/1000 = 0.388
So there is 38.8% probability that that is mild reaction
Solution(1c)
We need to calculate P(S) = ?
Here S is strong reaction
P(S) can be calculated as
P(S) = Total number of Strong reaction / Total No. of sample = 166/1000 = 0.166
So there is 16.6% probability that that is strong reaction.
Solution(2a)
We need to calculate P(N|W) which can be calculated as
P(N | W) = P(No reaction and within 5 miutes)/P(W) = (396/1000)/(500/1000) = 0.792
P(N | W) = 0.792 or 79.2%
Solution(2b)
We need to calculate P(S | W) which can be calculated as
P(S | W) = P(Strong reaction and within 5 miutes)/P(W) = (43/1000)/(500/1000) = 0.086
P(N | W) = 0.0.086 or 8.6%
Solution(3a)
We need to calculate P(N | A) which can be calculated as
P(N | A) = P(No reaction and After 5 miutes)/P(A) = (50/1000)/(500/1000) = 50/500 = 0.1
P(N | A) = 0.1 or 10%
Solution(3b)
We need to calculate P(S | A) which can be calculated as
P(S | A) = P(Strong reaction and After 5 miutes)/P(A) = (123/1000)/(500/1000) = 0.246
P(S | A) = 0.246
Solution(4a)
We need to calculate P(N and W) which can be calculated as
P(N and W) = P(No reaction and within 5 miutes) = (396/1000) = 0.396
P(N and W) = 0.396
Solution(4b)
We need to calculate P(M and W) which can be calculated as
P(M and W) = P(Mild reaction and within 5 miutes) = (61/1000) = 0.061
P(M and W) = 0.061
Solution(4c)
We need to calculate P(N or M) which can be calculated as
P(N or M) = P(No reaction) + P(Mild Reaction) - P(No reaction and Mild reaction) = 446/1000 + 388/1000 -0/1000 = 834/1000 = 0.834
P(N or M) = 0.834


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