Question

In: Statistics and Probability

1. In a study of vehicle ownership, it has been found that 30% of U.S. households...

1. In a study of vehicle ownership, it has been found that 30% of U.S. households do not own a vehicle, with 46% owning 1 vehicle, and the remaining owning 2 or more vehicles. The data for a random sample of 192 households in a resort community are as follows:

57 owned 0 vehicles, 104 owned 1 vehicle, and the remaining owned 2 or more vehicles.

When testing (at the 5% level of significance) whether the vehicle-ownership distribution in this community differs from that of the nation as a whole what is the test statistic? (please round your answer to 3 decimal places)

2. When testing (at the 5% level of significance) whether the vehicle-ownership distribution in this community differs from that of the nation as a whole what is the test statistic? (please round your answer to 3 decimal places)

In a study of vehicle ownership, it has been found that 29% of U.S. households do not own a vehicle, with 45% owning 1 vehicle, and the remaining owning 2 or more vehicles. The data for a random sample of 203 households in a resort community are as follows:

77 owned 0 vehicles, 106 owned 1 vehicle, and the remaining owned 2 or more vehicles.

When testing (at the 10% level of significance) whether the vehicle-ownership distribution in this community differs from that of the nation as a whole what is the critical value? (please round your answer to 3 decimal places)

Solutions

Expert Solution

Que.1

We use chi-square test to the following hypothesis:

Hypothesis:

H0 : The vehicle-ownership distribution in this community same as that of the nation.

Ha : The vehicle-ownership distribution in this community differs from that of the nation.

Observation table:

No. of vehicle Pi Observed freq (Oi) Expected Freq (Ei) = Npi (Oi - Ei)2/Ei
0 0.3 57 57.6 0.00625
1 0.46 104 88.32 2.78376812
2 or more 0.24 31 46.08 4.93503472
192 7.72505284

Test statistic,

Where,

n = Total number of observations

s = number of parameter estimated

k= number of degrees of freedom lost due to pooling

Hence degrees of freedom = n-s-k-1 = 3 - 0-0-1 = 2

Critical value = 5.99

Since calculated value of chi-square is greater than critical value we reject null hypothesis and conclude that the vehicle-ownership distribution in this community differs from that of the nation at 5% level of significance.

Que.2

Hypothesis:

H0 : The vehicle-ownership distribution in this community same as that of the nation.

Ha : The vehicle-ownership distribution in this community differs from that of the nation.

Observation table:

No. of vehicle Pi Observed freq (Oi) Expected Freq (Ei) = Npi (Oi - Ei)2/Ei
0 0.29 77 58.87 5.58343639
1 0.45 106 91.35 2.34945265
2 0.26 20 52.78 20.3586283
203 28.2915173

Where,

n = Total number of observations

s = number of parameter estimated

k= number of degrees of freedom lost due to pooling

Hence degrees of freedom = n-s-k-1 = 3 - 0-0-1 = 2

Critical value = 5.99

Since calculated value of chi-square is greater than critical value we reject null hypothesis and conclude that the vehicle-ownership distribution in this community differs from that of the nation at 5% level of significance.

Critical value at 10% level of significance = 4.605

Since calculated value of chi-square is greater than critical value we reject null hypothesis and conclude that the vehicle-ownership distribution in this community differs from that of the nation at 10% level of significance.


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